Question

What is the vertex form of `y= 15x^2-x-2`?

Answer 1

`y = 15(x - 1/30)^2 - 121/60`

Explanation:

`f(x) = 15x^2 - x - 2`
x-coordinate of vertex:
`x = -b/(2a) = 1/30`
y-coordinate of vertex:
`f(1/30) = 15/900 - 1/30 - 2 = 1/60 - 1/30 - 2 = - 121/60`
Vertex form:
`y = 15(x - 1/30)^2 - 121/60`