What is the vertex form of $y = - 25 x^{2} - 4 x + 3$ $y = −25x^2 − 4x+3$ ?

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Answer 1 · 2016-01-27T15:52:43

$y = - 25 {(x + \frac{2}{25})}^{2} - \frac{129}{625}$ $y = -25(x+2/25)^2 - 129/625$

The equation needs to be rewritten into the form $y = a {(x - h)}^{2} + k$ $y = a(x-h)^2 +k$ , where $(h, k)$ $(h,k)$ is the vertex.

$y = - 25 (x^{2} + \frac{4}{25} x - \frac{3}{25})$ $y=-25(x^2 +4/25x -3/25)$

$y = - 25 {(x + \frac{2}{25})}^{2} - \frac{4}{625} - \frac{3}{25}$ $y = -25(x+2/25)^2 -4/625 -3/25$

$y = - 25 {(x + \frac{2}{25})}^{2} - \frac{129}{625}$ $y = -25(x+2/25)^2 - 129/625$

The vertex is $(- \frac{2}{25}, - \frac{129}{625})$ $(-2/25,-129/625)$

What is the vertex form of y = −25x^2 − 4x+3 y=−25x2−4x+3 y = −25x^2 − 4x+3 ?