Question

What is the vertex form of `y= 25x^2 + 5x`?

Answer 1

The vertex form of equation is `y=25 (x+0.1)^2 - 0.25`

Explanation:

`y= 25 x^2+5 x or y = 25 (x^2+0.2 x)` or

`y=25 (x^2+0.2 x +0.1^2) -25*0.01` or

`y=25 (x+0.1)^2 - 0.25` . Comparing with vertex form of

equation `f(x) = a(x-h)^2+k ; (h,k)` being vertex we find

here `h= -0.1 , k= -0.25 :.` Vertex is at `(-0.1,-0.25)`

The vertex form of equation is `y=25 (x+0.1)^2 - 0.25`

graph{25x^2+5x [-5, 5, -2.5, 2.5]}