Question

What is the vertex form of `y=2x^2 +11x-6`?

Answer 1

`y = (x + 11/4)^2 - 169/8`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = -11/4`
y-coordinate of vertex:
`y(-11/4) = 2(121/16) - 121/4 - 6 = -121/8 - 48/8 = -169/8`
Vertex form:
`y = (x + 11/4)^2 - 169/8`