What is the vertex form of $y=2x^2 – 3x – 5$ ?

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Answer 1 · 2016-08-18T11:15:59

Vertex form of $y=2x^2-3x-5$ is $y=2(x-3/4)^2-49/8$

$y=2x^2-3x-5=2(x^2-3/2x)-5=2(x^2-3/2x+9/16)-9/8-5=2(x-3/4)^2-49/8:.$ Vertex is at $(3/4,-49/8)$ graph{2x^2-3x-5 [-20, 20, -10, 10]}[Ans]

What is the vertex form of y=2x^2 – 3x – 5 y=2x^2 – 3x – 5 ?