What is the vertex form of $y=2x^2+3x-8$ ?

Question

2719 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-27T11:42:31

Vertex form is $y = 2 (x + 3/4)^2 - 73/8$

$y = 2x^2 +3x -8 or y = 2 (x^2+3/2x) -8$ or

$y = 2 (x^2+3/2x + (3/4)^2 ) - 2*9/16-8$ or

$y = 2 (x + 3/4)^2 - 9/8-8$ or

$y = 2 (x + 3/4)^2 - 73/8$

Vertex is $(-3/4 , -9 1/8)$

Vertex form is $y = 2 (x + 3/4)^2 - 73/8$ [Ans]

What is the vertex form of y=2x^2+3x-8y=2x^2+3x-8?