What is the vertex form of y= (2x-3)(3x-12)+4x^2+5xy=(2x−3)(3x−12)+4x2+5x?

1 Answer
Binayaka C.
Apr 16, 2016

In Vertex form y=10*(x-7/5)^2+82/5y=10⋅(x−75)2+825

Explanation:

y=(2x-3)(3x-12)+4x^2+5x or y=6x^2-33x+36+4x^2+5x or y=10x^2-28x+36 or y = 10(x^2-14/5*x+(7/5)^2)-98/5+36 or y=10*(x-7/5)^2+82/5. Vertex is at (7/5,82/5) graph{10(x-7/5)^2+82/5 [-160, 160, -80, 80]}[Ans]

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