What is the vertex form of y= (2x-3)(7x-12)+17x^2-13x?

1 Answer
Jan 9, 2017

Vertex form of equation is y=31(x-29/31)^2+275/31

Explanation:

Vertex form of equation is y=a(x-h)^2+k

As we have y=(2x-3)(7x-12)+17x^2-13x

=2x xx 7x-2x xx12-3xx7x-3xx(-12)+17x^2-13x

=14x^2-24x-21x+36+17x^2-13x

=14x^2-24x-21x+36+17x^2-13x

=31x^2-58x+36

=31(x^2-58/31x)+36

=31(x^2-2xx29/31x+(29/31)^2)+36-31xx(29/31)^2

=31(x-29/31)^2+36-841/31

=31(x-29/31)^2+275/31
graph{(2x-3)(7x-12)+17x^2-13x [-5, 5, -2.88, 37.12]}