What is the vertex form of y=3x^2 +10x - 8 ?

1 Answer
Dec 29, 2017

y=3(x+5/3)^2-49/3

Explanation:

"the equation of a parabola in "color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))

"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"

"to obtain this form use the method of "color(blue)"completing the square"

• " the coefficient of the "x^2" term must be 1"

rArry=3(x^2+10/3x)-8

• " add/subtract "(1/2"coefficient of x-term")^2" to"
x^2+10/3x

rArry=3(x^2+2(5/3)xcolor(red)(+25/9)color(red)(-25/9))-8

color(white)(rArry)=3(x+5/3)^2-75/9-8

rArry=3(x+5/3)^2-49/3larrcolor(red)"in vertex form"