Question

What is the vertex form of `y=3x^2+11x-4`?

Answer 1

Vertex `(-11/6, -73/12)`

Explanation:

`y = 3x^2 + 11x - 4`
x-coordinate of vertex:
`x = -b/(2a) = - 11/6`
y-coordinate of vertex:
`y(-11/6) = 3(121/36) - 11(11/6) - 4 = 121/12 - 242/12 - 48/12 = - 73/12`
Vertex `(-11/6, -73/12)`