What is the vertex form of $y=3x^2+12x+4$ ?

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Answer 1 · 2017-02-10T16:52:32

y= $3(x+2)^2 -8$

Vertex is (-2,-8)

$y= 3(x^2 +4x) +4$

= $3(x^2 +4x +4-4) +4$

= $3(x^2+4x+4) -12+4$

= $3(x+2)^2 -8$

This is the required vertex form. The vertex of the parabola is(-2,-8).

What is the vertex form of y=3x^2+12x+4y=3x^2+12x+4?