What is the vertex form of #y=(3x - 2) (4x + 1) #?

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Answer 1 · 2018-08-11T03:47:51

#y=12(x-.208)^2-2.52#

First put the function into standard form by foiling:

#y=12x^2-5x-2#

Find the vertex: #x=-b/(2a)#

#x=5/24# = #.208#

plug that into the original equation:

#300/576-25/24-2# = #-2.52#

vertex#(h,k)#: (#.208#,#-2.52#)

put it into #y=a(x-h)^2+k# form:

#y=12(x-.208)^2-2.52#
graph{y=12(x-.208)^2-2.52 [-10, 10, -5, 5]}