Question

What is the vertex form of `y=-3x^2 + 6x -2`?

Answer 1

`y = -3(x - 1)^2 + 1`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = -6/-6 = 1`
y-coordinate of vertex:
y(1) = -3 + 6 - 2 = 1
Vertex (1, 1)
Vertex form of y;
`y = a(x + b/(2a))^2 + y(-b/(2a)`
`y = -3(x - 1)^2 + 1`