What is the vertex form of $y=-3x^2-6x-3$ ?

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Answer 1 · 2017-06-15T05:40:44

$y=-3(x+1)^2$

Given -

$y=-3x^2-6x-3$

Vertex -

x-coordinate of the vertex

$x=(-b)/(2a)=(-(-6))/(2 xx(-3))=6/(-6)=-1$

Y-coordinate of the vertex

At $x=-1$

$y=-3(-1)^2-6(-1)-3=-3+6-3=0$

Vertex $(-1,0)$

Vertex form of the equation is -

$y=a(x-h)^2+k$

$a=-3$ - coefficient of $x^2$
$h=-1$
$k=2$

$y=-3(x+1)^2+0$

$y=-3(x+1)^2$

What is the vertex form of y=-3x^2-6x-3y=-3x^2-6x-3?