What is the vertex form of y = -3x^2+9x+1?

1 Answer
Dec 6, 2015

y=-3(x-3/2)^2+31/4

Explanation:

Given:color(white)(..)y=-3x^2+9x+1...........(1)

Write as:color(white)(..)y=-3(x^2color(green)(-3x))+1

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Consider the RHS only

Write as: -3(x-3/2)^2+1.............................(2)

The (-3/2) comes from halving the coefficient of x " in "color(green)( -3x)

Expression (2) has an inherent error which we need to correct

-3(x-3/2)^2
=-3( x^2 -3x+9/4)
= -3x^2+9x-27/4...................(3)

Add the constant of +1 as shown in equation (1) giving

= -3x^2+9x-27/4 + 1...................(3_a)

When you compare (3_a) to (1) you see that the error introduced is -27/4

We correct for this by removing it from the vertex form equations using color(blue)(+27/4)

Thus the underline(color(red)("incorrect")) form of y=-3(x-3/2)^2+1 color(blue)(" is adjusted by:")

y=-3(x-3/2)^2+1color(blue)(+27/4)

Giving:

y=-3(x-3/2)^2color(brown)(+31/4)