What is the vertex form of y=4/5x^2-3/8x+3/8y=45x2−38x+38?
1 Answer
Dec 4, 2017
Explanation:
"the equation of a parabola in "color(blue)"vertex form"the equation of a parabola in vertex form is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"
"given the equation in standard form "ax^2+bx+c
"then the x-coordinate of the vertex is"
•color(white)(x)x_(color(red)"vertex")=-b/(2a)
y=4/5x^2-3/8x+3/8" is in standard form"
"with "a=4/5,b=-3/8 and "c=3/8
rArrx_(color(red)"vertex")=-(-3/8)/(8/5)=15/64
"substitute this value into the equation for y"
y=4/5(15/64)^2-3/8(15/64)+3/8=339/1024
rArry=(x-15/64)^2+339/1024larrcolor(red)"in vertex form"