What is the vertex form of y=4x^2-13x-6?

1 Answer
Jim H
Aug 13, 2017

y = 4(x-13/8)^2-265/16

Explanation:

y = 4x^2-13x-6

= 4(x^2-13/4xcolor(white)"XXXXXX") -6

1/2 * 13/4 = 13/8 and (13/8)^2 = 169/64

So inside the parentheses add 169/64

Outside the parentheses subtract 4 * 169/64 = 169/16

y = 4(x^2-13/4+169/64) - 169/16 - 96/16

To finish, factor the expression in parentheses and simplify the subtraction outside the parentheses.

y = 4(x-13/8)^2-265/16

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