What is the vertex form of y= 4x^2 + 17x + 4 ?

1 Answer
Nghi N.
Jan 10, 2016

y = 4(x + 17/8)^2 - 140.5

Explanation:

First, find x-coordinate of vertex:
x = -b/(2a) = -17/8
Next, find y-coordinate of vertex
y(-17/8) = 4(289/64) - 17(17/8) + 4 = 1156/64 - 289/8 + 4 = = -1156/8 + 32/8 = - 1124/8 = -140.5
Vertex form:
y = 4(x + 17/8)^2 - 140.5

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