What is the vertex form of y=4x2−32x+63?

1 Answer
Nallasivam V
Jan 15, 2016

y=4(x−4)2−1

Explanation:

If the standard form of a quadratic equation is -

y=ax2+bx+c
Then -

Its vertex form is -

y=a(x−h)2+k
Where -

a=co-efficient of x
h=−b2a
k=ah2+bh+c

Use the formula to change it to vertex form -

y=4x2−32x+63
a=4
h=−(−32)2×4=328=4
k=4(4)2−32(4)+63
k=64−128+63
k=127−128=−1

Substitute a=4;h=4:k=−1 in

y=a(x−h)2+k
y=4(x−4)2−1

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