What is the vertex form of $y=-4x^2+4x-1$ ?

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Answer 1 · 2018-04-29T11:33:16

$y=-4(x+1/2)^2$

Take $-4$ as a common factor

$y=-4(color(green)(x^2-x)+1/4)$

By completing the Square to the elements in green

$y=-4(color(green)((x-1/2)^2-1/4)+1/4)$

$y=-4(x+1/2)^2$

The Function represents a parabola with the vertex $(-1/2,0)$ and opened downwards

What is the vertex form of y=-4x^2+4x-1 y=-4x^2+4x-1 ?