Question

What is the vertex form of `y=4x^2-8x+16`?

Answer 1

Vertex (1, 12)
`y = 4(x - 1)^2 + 12`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = 8/8 = 1`
y-coordinate of vertex:
y(1) = 4 - 8 + 16 = 12
Vertex (1, 12)
Vertex form of y:
`y = a(x + b/(2a))^2 + y(-b/(2a))`
`y = 4(x - 1)^2 + 12`