What is the vertex form of y= 4x^2 - 8x + 3 ? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Roella W. Dec 23, 2015 y = 4(x-1)^2 -1 Explanation: Vertex form is y = (ax +b)^2 +c . In this case a = 2 and b = - 2 (2x -2)^2 = 4x^2 - 8x + 4 so we need to subtract 1 y = (2x-2)^2 -1 which is better expressed as y = 4(x-1)^2 -1 Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 5247 views around the world You can reuse this answer Creative Commons License