What is the vertex form of y=4x^2+x-4+10 ?

1 Answer
Nov 11, 2017

y=4(x+1/8)^2+95/16

Explanation:

"the equation of a parabola in "color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))

"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"

"to express in this form use "color(blue)"completing the square"

y=4x^2+x+6

• " coefficient of "x^2" term must be 1"

rArry=4(x^2+1/4x+3/2)

• " add/subtract "(1/2"coefficient of x-term")^2

"to "x^2+1/4x

rArry=4(x^2+2(1/8)xcolor(red)(+1/64)color(red)(-1/64)+3/2)

color(white)(rArry)=4(x+1/8)^2+(4xx95/64)

color(white)(rArry)=4(x+1/8)^2+95/16