What is the vertex form of $y=5x^2-11$ ?

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Answer 1 · 2016-05-30T10:10:06

$y=5x^2-11$

Though the equation is in the standard form.
Its vertex form is the same.

The vertex form of the equation can be written as

$y=a(x-h)^2+k$

Here $h$ is the x-coordinate of the vertex.
$k$ is the y - coordinate of the vertex.

$a$ is the co-efficient of $x^2$
Its vertex is $(0, -11)$
$a=5$
Then
$y=5(x-(0))^2-11$
$y=5x^2-11$

What is the vertex form of y=5x^2-11 y=5x^2-11 ?