What is the vertex form of y= -5x^2-2x+24 ? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Binayaka C. Aug 21, 2017 The vertex form is y = -5(x+0.2)^2+ 24.2 Explanation: y = -5x^2-2x+24 or y = -5(x^2+2/5x) +24 or y = -5(x^2+2/5x +1/25)+1/5 +24 or y = -5(x+1/5)^2+ 121/5 or y = -5(x+0.2)^2+ 24.2 . Comparing with vertex form of equation y = a(x-h)^2 +k ; (h,k) being vertex , we find here h= -0.2 , k =24.2 . So vertex is at (-0.2,24.2). The vertex form is y = -5(x+0.2)^2+ 24.2 [Ans] Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1681 views around the world You can reuse this answer Creative Commons License