What is the vertex form of #y= 5x^2-2x – 6 #?

1 Answer
Jul 29, 2016

See explanation

Explanation:

#color(blue)("Step 1")#

Write as: #y=5(x^2-2/5x)-6+k#

where #k# is a correction for an error that will be introduced by the method.
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Step 2")#
#color(brown)("Move the power to outside the brackets")#

#y=5(x-2/5x)^2-6+k#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Step 3")#
#color(brown)("Halve the "2/5)#

#y=5(x-2/10x)^2-6+k#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Step 4")#
#color(brown)("Remove the "x" from "-2/10x)#

#y=5(x-2/10)^2-6+k#

#color(green)("Now we need to determine the value of "k)#
,~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Step 5")#

The squaring the #-2/10" " ->+4/100#

Now multiply it by the 5 #->5xx4/100 = 4/20-=1/5#

So #1/5+k=0=> k=-1/5# giving

#" "color(purple)(bar(ul(|color(white)((2/2)/2)y=5(x-1/5)^2-31/5color(white)(2/2)|)))#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(white)(.)#

Tony B