Question

What is the vertex form of `y=-5x^2-3x+1`?

Answer 1

`y=-5(x+3/10)^2+29/20`

Explanation:

We need to transform this function into this type `y=a(x-h)^2+k`
So`y=-5x^2-3x+1`
`=>y=-5(x^2+3/5x)+1`
`=>y=-5(x^2+3/5x+9/100)+1+9/20`
Final
`=>y=-5(x+3/10)^2+29/20`