What is the vertex form of $y= 5x^2-9x-2$ ?

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Answer 1 · 2018-03-16T14:18:08

$5(x-9/10)^2-121/20$

We have to write the above in the form $a(x-h)^2+k$

We have:

$5x^2-9x-2$

$5(x^2-9/5x)-2$

$5(x^2-9/5x+81/100)-2-81/20$

$5(x-9/10)^2-121/20$

This is in the above form.

By the way, the vertex is at $(9/10,-121/20)$

What is the vertex form of y= 5x^2-9x-2 y= 5x^2-9x-2 ?