What is the vertex form of $y= 6x^2 + 12x – 48$ ?

Question

3047 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-31T09:58:57

$y = 6(x+1)^2 -54$

First simplify the expression
$y = 6(x^2 +2x - 8)$
Then use completing the square
$y = 6((x+1)^2 - 9)$
$y = 6(x+1)^2 -54$
The vertex is $(-1,-54)$

What is the vertex form of y= 6x^2 + 12x – 48 y= 6x^2 + 12x – 48 ?