What is the vertex form of y=6x^2-13x-5 y=6x2−13x−5?
1 Answer
Mar 2, 2016
Explanation:
The standard form of the quadratic function is
ax^2+bx+c ax2+bx+c the function here
y = 6x^2-13x-5 " is in this form " y=6x2−13x−5 is in this form by comparison , a = 6 , b = -13 and c = -5
The vertex form is :
y=a(x-h)^2 + k y=a(x−h)2+k where (h,k) are the coords of the vertex.
the x-coord of the vertex (h)
= (-b)/(2a) = -(-13)/12 = 13/12=−b2a=−−1312=1312 and y-coord (k)
= 6(13/12)^2 -13(13/12) - 5 = -289/24 =6(1312)2−13(1312)−5=−28924 here
(h,k) = (13/12 , -289/24 ) and a = 6 (h,k)=(1312,−28924)anda=6
rArr y = 6(x-13/12)^2 - 289/24 " is the equation " ⇒y=6(x−1312)2−28924 is the equation
