What is the vertex form of $y = 6 x^{2} - 7 x + 8$ $y=6x^2-7x+8$ ?

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What is the vertex form of $y = 6 x^{2} - 7 x + 8$ $y=6x^2-7x+8$ ?

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Answer 1 · 2016-02-27T05:14:31

It is $y = 6 \cdot {(x - \frac{7}{2})}^{2} + \frac{143}{24}$ $y=6*(x-7/2)^2+143/24$

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$y = 6 x^{2} - 7 x + 8 \Rightarrow y = 6 \cdot [x^{2} - 2 \cdot 7 \cdot \frac{x}{12} + {(\frac{7}{12})}^{2}] + 8 - \frac{49}{24} \Rightarrow y = 6 \cdot {(x - \frac{7}{2})}^{2} + \frac{143}{24}$ $y=6x^2-7x+8=> y=6*[x^2-2*7*x/12+(7/12)^2]+8-49/24=> y=6*(x-7/2)^2+143/24$

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What is the vertex form of $y = 6 x^{2} - 7 x + 8$ $y=6x^2-7x+8$ ?

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What is the vertex form of y=6x^2-7x+8y=6x2−7x+8y=6x^2-7x+8?

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What is the vertex form of $y = 6 x^{2} - 7 x + 8$ $y=6x^2-7x+8$ ?