What is the vertex form of y=7x^2-14x-6 ? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Bill Jorgensen Jun 16, 2018 y=7(x-2)^2-13 Explanation: y=7x^2-14x-6 y+6=7x^2-14x y+6=7(x^2-2x) y+6 + 7c=7(x^2-2x+c) c=(-2/2)^2= 1 y+6 + 7*1=7(x^2-2x+1) y+13=7(x-2)^2 y=7(x-2)^2-13 Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 3008 views around the world You can reuse this answer Creative Commons License