What is the vertex form of $y = x^{2} - 11 x + 30$ $y= x^2 - 11x + 30$ ?

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Answer 1 · 2017-05-15T11:43:04

The vertex form is $y = {(x - \frac{11}{2})}^{2} - \frac{1}{4}$ $y= (x - 11/2)^2 -1/4$

$y = x^{2} - 11 x + 30 or y = (x^{2} - 11 x + {(\frac{11}{2})}^{2}) - \frac{121}{4} + 30$ $y= x^2-11x+30 or y= (x^2 -11x +(11/2)^2) -121/4 + 30$ or

$y = {(x - \frac{11}{2})}^{2} - \frac{1}{4}$ $y= (x - 11/2)^2 -1/4$ . Vertex is at $\frac{11}{2}, - \frac{1}{4}$ $11/2 , -1/4$

The vertex form is $y = {(x - \frac{11}{2})}^{2} - \frac{1}{4}$ $y= (x - 11/2)^2 -1/4$ [Ans]

What is the vertex form of y=x2−11x+30y= x^2 - 11x + 30?