What is the vertex form of $y=x^2+12x+36$ ?

Question

4382 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-06T01:06:26

Vertex form pf y = x^2 + 12x + 36.

y = (x + 6)^2
x-coordinate of vertex:
(x + 6) = 0--> x = - 6
y-coordinate of vertex: y = y(-6) = 36 - 72 + 36 = 0
Vertex form: y = (x + 6)^2

What is the vertex form of y=x^2+12x+36 y=x^2+12x+36 ?