What is the vertex form of y=−x2−17x−15?
1 Answer
Feb 11, 2016
y=−1(x+174)2+5714
Explanation:
Given -
y=−x2−17x−15
Find the vertex -
x=−b2a=−(−17)2×(−1)=17−2=−172
y=−(−172)2−17(−172)−15
y=−(7214)+14412−15
y=−7214+14412−15
y=5714
Vertex is
The vertex form of the quadratic equation is -
y=a(x−h)2+k
Where -
a=−1 Coefficient ofx2
h=−174 x co-ordinate of the vertex
k=5714 y co-ordinate of the vertex
Now substitute these values in the vertex formula.
y=−1(x−(−174))2+(5714)
y=−1(x+174)2+5714
