What is the vertex form of $y=x^2/2 +10x + 22$ ?

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Answer 1 · 2017-10-24T20:03:23

The vertex form of $y=x^2/2+10x+22$ is $y=(x+5)^2-3$

Let's start with the original equation:

$y=x^2/2+10x+22$

In order to turn this equation into vertex form, we're going to complete the square:

$y+(10/2)^2=x^2+10x+(10/2)^2+22$

$y+25=(x+5)^2+22$

$y=(x+5)^2-3$

What is the vertex form of y=x^2/2 +10x + 22 y=x^2/2 +10x + 22 ?