What is the vertex form of #y=x^2 -2x-15?

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Answer 1 · 2018-05-09T11:07:12

Vertex form of equation is $y= (x -1)^2 -16$

$y=x^2 -2 x -15$ or

$y=(x^2 -2 x + 1) -16$ or

$y=(x -1)^2 -16$ Comparing with vertex form of

equation $y = a(x-h)^2+k ; (h,k)$ being vertex we find

here $h=1 , k= -16 :.$ Vertex is at $(1,-16)$ )# and vertex

form of equation is $y= (x -1)^2 -16$

graph{x^2-2x-15 [-40, 40, -20, 20]} [Ans]