What is the vertex form of y= (x+2) (2x+5) ?
1 Answer
Mar 10, 2018
Explanation:
"the equation of a parabola in "color(blue)"vertex form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
"where "(h,k)" are the coordinates of the vertex and a "
"is a multiplier"
y=(x+2)(2x+5)larrcolor(blue)"expand the factors"
color(white)(y)=2x^2+9x+10
"to obtain vertex form use "color(blue)"completing the square"
• " the coefficient of the "x^2" term must be 1"
rArry=2(x^2+9/2x+5)
• " add/subtract "(1/2"coefficient of the x-term")^2" to"
x^2+9/2x
rArry=2(x^2+2(9/4)xcolor(red)(+81/16)color(red)(-81/16)+5)
color(white)(y)=2(x+9/4)^2+2(-81/16+5)
color(white)(y)=2(x+9/4)^2-1/8larrcolor(red)"in vertex form"