What is the vertex form of y= (x+2) (2x+5) ?

1 Answer
Mar 10, 2018

y=2(x+9/4)^2-1/8

Explanation:

"the equation of a parabola in "color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))

"where "(h,k)" are the coordinates of the vertex and a "
"is a multiplier"

y=(x+2)(2x+5)larrcolor(blue)"expand the factors"

color(white)(y)=2x^2+9x+10

"to obtain vertex form use "color(blue)"completing the square"

• " the coefficient of the "x^2" term must be 1"

rArry=2(x^2+9/2x+5)

• " add/subtract "(1/2"coefficient of the x-term")^2" to"
x^2+9/2x

rArry=2(x^2+2(9/4)xcolor(red)(+81/16)color(red)(-81/16)+5)

color(white)(y)=2(x+9/4)^2+2(-81/16+5)

color(white)(y)=2(x+9/4)^2-1/8larrcolor(red)"in vertex form"