What is the vertex form of $y=x^2 + 35x + 36$ ?

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Answer 1 · 2017-12-05T07:01:51

$y=(x+17.5)^2-270.25$

Given -

$y=x^2+35x+36$

Vertex

$x=(-b)/(2a)=(-35)/(2xx1)=(-35)/2=-17.5$

At $x=-17.5$

$y= (-17.5)^2+35(-17.5)+36$
$y= (-17.5)^2+35(-17.5)+36$
$y=306.25-612.5+36=-270.25$

$(-17.5, -270.25)$

Vertex form

$y=a(x-h)^2+k$

Where -

$a=$ coefficient of $x^2$
$h=-17.5$
$k=-270.25$

Then substitute -

$y=(x-(-17.5))^2+(-270.25)$

$y=(x+17.5)^2-270.25$

What is the vertex form of y=x^2 + 35x + 36y=x^2 + 35x + 36?