What is the vertex form of y=x^2 - 3x +4?

1 Answer
Jun 5, 2017

y=(x-3/2)^2+7/4

Explanation:

"the equation of a parabola in vertex form is"

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
where ( h , k ) are the coordinates of the vertex and a is a constant.

"for a parabola in standard form " y=ax^2+bx+c

x_(color(red)"vertex")=-b/(2a)

y=x^2-3x+4" is in this form"

"with " a=1,b=-3,c=4

rArrx_(color(red)"vertex")=-(-3)/2=3/2

"substitute this value into function to obtain y"

rArry_(color(red)"vertex")=(3/2)^2-(3xx3/2)+4=7/4

rArrcolor(magenta)"vertex "=(3/2,7/4)

rArry=(x-3/2)^2+7/4larrcolor(red)" in vertex form"