What is the vertex form of $y= x^2 – 3x – 40$ ?

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Answer 1 · 2016-02-28T04:49:01

$(x-3/2)^2=y+169/4" " "$ the Vertex Form

From the given $y=x^2-3x-40$ perform "Completing the square method#

$y=x^2-3x-40$

We add and subtract $9/4$ to complete the square

$y=x^2-3x+9/4-9/4-40$

$y=(x-3/2)^2-169/4$

$y+169/4=(x-3/2)^2$

$(x-3/2)^2=y+169/4" " "$ the Vertex Form

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What is the vertex form of y= x^2 – 3x – 40y= x^2 – 3x – 40?