What is the vertex form of $y=x^2+45x+31$ ?

Question

1645 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-22T11:48:57

Vertex form of equation is $y= (x+22.5)^2 - 475.25$

$y = x^2+45x+31 or y = x^2 + 45x +(45/2)^2 - (45/2)^2 +31$

$y= (x+45/2)^2 -2025/4 +31 or y= (x+45/2)^2 - 1901/4$ or

$y= (x+22.5)^2 - 475.25$ . Comparing with vertex form of

equation $y = a(x-h)^2+k ; (h,k)$ being vertex , we find here

$h= -22.5 , k = -475.25 :.$ Vertex is at $( -22.5 ,-475.25)$

and vertex form of equation is $y= (x+22.5)^2 - 475.25$ [Ans]

What is the vertex form of y=x^2+45x+31y=x^2+45x+31 ?