What is the vertex form of $y=x^2 - 4x + 14$ ?

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Answer 1 · 2016-03-19T14:47:07

$y = 1(x-2)^2+10$

Complete the square to rearrange into vertex form:

$y = x^2-4x+14$

$=x^2-4x+4+10$

$=(x-2)^2+10$

$=1(x-2)^2+10$

The equation:

$y = 1(x-2)^2+10$

is in the form:

$y = a(x-h)^2+k$

which is the equation of a parabola with vertex at $(h,k) = (2,10)$ and multiplier $1$ .

What is the vertex form of y=x^2 - 4x + 14 y=x^2 - 4x + 14 ?