What is the vertex form of $y=x^2-6x+15$ ?

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Answer 1 · 2016-07-12T03:13:52

$y = (x - 3)^2 + 6$

x-coordinate of vertex:
$x = -b/(2a) = 6/2 = 3$
y-coordinate of vertex
$y(3) = 9 - 18 + 15 = 6$
vertex (3, 6)
Vertex form of y:
$y = (x - 3)^2 + 6$

What is the vertex form of y=x^2-6x+15 y=x^2-6x+15 ?