Question

What is the vertex form of `y= x^2 + 6x + 36`?

Answer 1

`y = (x + 3)^2 + 27.`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = -6/2 = -3`
y-coordinate of vertex:
y(-3) = 9 - 18 + 36 = 27
Vertex (-3, 27)
Vertex form: `y = (x + 3)^2 + 27`.