What is the vertex form of $y= x^2 - 7x + 10$ ?

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Answer 1 · 2017-11-15T21:47:20

When given a quadratic of the form, $y=ax^2+bx+c$ , the vertex form is $y=a(x+b/(2a))^2-b^2/(4a)+c$

For the given equation, $y= x^2 - 7x + 10$ , $a = 1$ , $b = -7$ , and #c = 10.

Substitute these values into the vertex form, $y=a(x+b/(2a))^2-b^2/(4a)+c$ :

$y=1(x+(-7)/(2(1)))^2-(-7)^2/(4(1))+10$

Simplify:

$y=1(x-7/2)^2-9/4$

What is the vertex form of y= x^2 - 7x + 10 y= x^2 - 7x + 10 ?