What is the vertex form of $y= x^2+7x-2$ ?

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Answer 1 · 2017-04-14T14:57:41

Vertex form is $y=(x+7/2)^2-57/4$ and vertex is $(-3 1/2,-14 1/4)$

$y=x^2+7x-2$

= $x^2+2×7/2×x+(7/2)^2-(7/2)^2-2$

= $(x+7/2)^2-49/4-2$

= $(x+7/2)^2-57/4$

Hence, vertex form is $y=(x+7/2)^2-57/4$ and vertex is $(-7/2,-57/4)$ or $(-3 1/2,-14 1/4)$

What is the vertex form of y= x^2+7x-2 y= x^2+7x-2 ?