What is the vertex form of $y= x^2+7x-30$ ?

Question

2306 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-31T01:29:33

$(y + 89/4) = (x + 7/2)^2$

$y= x^2 + 7x - 10$
transpose -10 to the right side of the equation, from negative it will change its sign into positive

$y +10 = x^2 +7x$

Complete the square of the right side of the equation
Get half of the coefficient of x, then raise it to the second power.

Mathematically as follows: $(7/2)^2$ = $49/4$

then add,
$49/4$ to both sides of the equation

$y +10 + 49/4 = x^2 +7x + 49/4$
simplify the right side and factor the left side

$(y +89/4) = (x + 7/2)^2$ $answer$

What is the vertex form of y= x^2+7x-30 y= x^2+7x-30 ?