What is the vertex form of $y=x^2+8x-1$ ?

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Answer 1 · 2016-11-07T01:11:03

The vertex form of $y=x^2+8x-1$ is y=(x+4)^2-17.

First find $-b/2=-4$ , so -4 will be added to x inside the parentheses.
Next, find $c-b^2$ to find the value you add at the end.

$y = (x-b/2)^2+c-b^2$
$y=(x+4)^2-17$

What is the vertex form of y=x^2+8x-1y=x^2+8x-1?