Question

What is the vertex form of `y= (x + 2)(x + 5)`?

Answer 1

Vertex form of `y=(x+2)(x+5)` is `y=(x+7/2)^2-9/4`

Explanation:

Vertex form of equation is `y=a(x-h)^2+k`, where `(h,k)` is the vertex.

Here we have `y=(x+2)(x+5)`

`=x^2+7x+10`

`=x^2+2xx7/2xx x+(7/2)^2-49/4+10`

`=(x+7/2)^2-9/4`

Hence vertex form of `y=(x+2)(x+5)` is `y=(x+7/2)^2-9/4`
graph{(x+2)(x+5) [-11.75, 8.25, -4.88, 5.12]}